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A238714
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Final divisor of A238529(n).
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1
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2, 3, 4, 5, 5, 7, 2, 3, 3, 11, 5, 13, 5, 7, 8, 17, 2, 19, 2, 10, 3, 23, 5, 5, 11, 9, 5, 29, 10, 31, 2, 5, 7, 11, 5, 37, 17, 7, 7, 41, 5, 43, 5, 11, 10, 47, 4, 7, 2, 11, 17, 53, 3, 7, 4, 13, 9, 59, 12, 61, 29, 11, 4, 11, 2, 67, 5, 17, 14, 71, 12, 73, 11, 3, 7, 5, 5
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OFFSET
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2,1
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COMMENTS
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Conjecture: Every integer greater than 1, except 6, is an element of the sequence.
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LINKS
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EXAMPLE
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a(8) = 2, because 8 mod sopfr(8) = 8 mod 6 = 2, and 2 mod sopfr(2) = 2 mod 2 = 0, and 2 is the last divisor used.
a(21) = 10, because 21 mod sopfr(21) = 21 mod 10 = 1, and 10 is the last divisor used.
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PROG
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(Python)
def primfacs(n):
i = 2
primfac = []
while i * i <= n:
while n % i == 0:
primfac.append(i)
n //= i
i += 1
if n > 1:
primfac.append(n)
return primfac
def sopfr(n):
plist = primfacs(n)
l = len(plist)
s = 0
while l > 0:
s += plist[l - 1]
l -= 1
return s
n = 2
max = 1000
lst = []
while n <= max:
rem = n
while rem > 1:
last = sopfr(rem)
rem = rem % last
lst.append(last)
n += 1
print(lst)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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