A236456 Number of ordered ways to write n = k + m with k > 0 and m > 0 such that p = phi(k) + phi(n-k)/4 - 1, q = p + 2 and r = prime(q) + 2 are all prime, where phi(.) is Euler's totient function.

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 2, 3, 3, 2, 4, 2, 2, 4, 5, 4, 2, 3, 1, 3, 2, 3, 4, 3, 4, 5, 0, 2, 2, 3, 2, 4, 2, 4, 3, 2, 2, 1, 2, 5, 2, 3, 1, 4, 2, 2, 4, 1, 4, 1, 5, 4, 2, 2, 1, 2, 1, 5, 3, 3, 1, 2, 2, 4, 1, 3, 4, 2, 2, 1, 0, 2, 4, 2, 1, 3, 1, 4, 3, 5, 3, 2, 1, 3, 2, 3, 2, 0

Offset

1,19

Comments

Conjecture: a(n) > 0 for all n > 357.

This is much stronger than the twin prime conjecture. Actually it implies that there are infinitely many primes p such that {p, p + 2} and {prime(p+2), prime(p+2) + 2} are both twin prime pairs. See A236457 for such primes p.

Links

Zhi-Wei Sun, Table of n, a(n) for n = 1..10000

Example

a(18) = 1 since 18 = 3 + 15 with phi(3) + phi(15)/4 - 1  = 3,  3 + 2 = 5 and prime(5) + 2 = 13 all prime.
a(50) = 1 since 50 = 16 + 34 with phi(16) + phi(34)/4 - 1 = 11, 11 + 2 = 13 and prime(13) + 2 = 43 all prime.
a(929) = 1 since 929 = 441 + 488 with phi(441) + phi(488)/4 - 1 = 252 + 60 - 1 = 311, 311 + 2 = 313 and prime(313) + 2 = 2083 all prime.

Mathematica

  p[n_]:=PrimeQ[n]&&PrimeQ[n+2]&&PrimeQ[Prime[n+2]+2]
f[n_, k_]:=EulerPhi[k]+EulerPhi[n-k]/4-1
a[n_]:=Sum[If[p[f[n, k]], 1, 0], {k, 1, n-1}]
Table[a[n], {n, 1, 100}]

Crossrefs

Cf. A000010, A000040, A001359, A006512, A236097, A236457, A236458.

Sequence in context: A090414 A068227 A235343 * A046824 A130156 A139169

Adjacent sequences: A236453 A236454 A236455 * A236457 A236458 A236459

Keyword

nonn

Author

Zhi-Wei Sun, Jan 26 2014

Status

approved