OFFSET
1,2
COMMENTS
Positions of records are at 2, 7, 9, 13, 19, 27, 35, 47, 63, 87, 117, 159, 217, 301, 413, ...
FORMULA
Conjecture: For n>4, a(n) = 2^L(n) - 2^F(n) - 1, with L(n) the Lucas numbers A000032, and F(n) the Fibonacci numbers.
MATHEMATICA
Rest[DeleteDuplicates[ContinuedFraction[Sum[2^-Fibonacci[k], {k, 2, 20}]], GreaterEqual]] (* Harvey P. Dale, Sep 04 2023 *)
PROG
(PARI) m=1; for(n=1, 500, t=contfrac(suminf(i=2, 1/2^fibonacci(i)))[n+1]; if(m<t, m=t; print1(t, ", ")))
CROSSREFS
KEYWORD
nonn
AUTHOR
Ralf Stephan, Jan 19 2014
STATUS
approved