

A232753


a(n) = the number of times needed to iterate Hofstadter's A030124, starting from A030124(1)=2, that the result were >= n; a(n) = the least k such that A232739(k) >= n.


4



1, 1, 2, 2, 3, 3, 4, 4, 4, 5, 5, 5, 5, 6, 6, 6, 6, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 13, 13, 13, 13, 14, 14, 14, 14, 14, 14, 14
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OFFSET

1,3


COMMENTS

Does the ratio a(n)/A232746(n) converge towards some limit?


LINKS



EXAMPLE

A030124(1)=2 (counted as the first iteration)
A030124(2)=4 (counted as the second iteration)
A030124(4)=6 (counted as the third iteration)
Thus a(4)=2 as we reached 4 in two iterations, but a(5) = a(6) = 3, as three iterations of A030124 are needed to reach a number that is larger than or equivalent to 5, or respectively, 6.


PROG



CROSSREFS



KEYWORD

nonn


AUTHOR



STATUS

approved



