

A231003


Number of years after which it is not possible to have a date falling on the same day of the week, in the Julian calendar.


1



1, 2, 3, 4, 7, 8, 9, 10, 12, 13, 14, 15, 16, 18, 19, 20, 21, 24, 25, 26, 27, 29, 30, 31, 32, 35, 36, 37, 38, 40, 41, 42, 43, 44, 46, 47, 48, 49, 52, 53, 54, 55, 57, 58, 59, 60, 63, 64, 65, 66, 68, 69, 70, 71, 72, 74, 75, 76, 77, 80, 81, 82, 83, 85, 86, 87, 88, 91, 92, 93, 94, 96, 97
(list;
graph;
refs;
listen;
history;
text;
internal format)



OFFSET

1,2


COMMENTS

In the Julian calendar, a year is a leap year if and only if it is a multiple of 4 and all century years are leap years.
Assuming this fact, this sequence is periodic with a period of 28.
This is the complement of A231000.


LINKS

Table of n, a(n) for n=1..73.
Time And Date, Repeating Calendar
Time And Date, Julian Calendar


PROG

(PARI) for(i=0, 420, j=0; for(y=0, 420, if(((5*(y\4)+(y%4))%7)==((5*((y+i)\4)+((y+i)%4))%7), j=1)); if(j==0, print1(i", ")))


CROSSREFS

Cf. A230995A231014.
Cf. A230998 (Gregorian calendar).
Sequence in context: A305441 A121405 A330217 * A171551 A096199 A104576
Adjacent sequences: A231000 A231001 A231002 * A231004 A231005 A231006


KEYWORD

nonn,easy


AUTHOR

Aswini Vaidyanathan, Nov 02 2013


STATUS

approved



