OFFSET
1,1
COMMENTS
The primitive areas are 6, 84, 108, 120, 132, 144, 156, 168, ...
The non-primitive areas 16*a(n) are in the sequence because if r is the inradius corresponding to a(n), then 4*r is the inradius corresponding to 16*a(n).
The following table gives the first values (A, r, a, b, c) where A is the integer area, r the inradius and a, b, c are the integer sides of the triangle.
******************************
* A * r * a * b * c *
*******************************
* 6 * 1 * 3 * 4 * 5 *
* 84 * 4 * 13 * 14 * 15 *
* 96 * 4 * 12 * 16 * 20 *
* 108 * 4 * 15 * 15 * 24 *
* 120 * 4 * 10 * 24 * 26 *
* 132 * 4 * 11 * 25 * 30 *
* 144 * 4 * 18 * 20 * 34 *
* 156 * 4 * 15 * 26 * 37 *
* 168 * 4 * 10 * 35 * 39 *
* 180 * 4 * 9 * 40 * 41 *
* 240 * 4 * 12 * 50 * 58 *
* 264 * 4 * 33 * 34 * 65 *
* 300 * 4 * 25 * 51 * 74 *
* 324 * 4 * 9 * 75 * 78 *
* 396 * 4 * 11 * 90 * 97 *
* 420 * 4 * 21 * 85 * 104 *
* 432 * 9 * 30 * 30 * 36 *
* 468 * 9 * 25 * 39 * 40 *
.........................
REFERENCES
Mohammad K. Azarian, Circumradius and Inradius, Problem S125, Math Horizons, Vol. 15, Issue 4, April 2008, p. 32. Solution published in Vol. 16, Issue 2, November 2008, p. 32.
LINKS
Eric W. Weisstein, MathWorld: Inradius
FORMULA
Area A = sqrt(s*(s-a)*(s-b)*(s-c)) with s = (a+b+c)/2 (Heron's formula) and inradius r = A/s.
EXAMPLE
84 is in the sequence because the area of triangle (13, 14, 15) is given by Heron's formula A = sqrt(21*(21-13)*(21-14)*(21-15))= 84 where the number 21 is the semiperimeter and the inradius is given by r = A/s = 84/21 = 4 is a square.
MATHEMATICA
nn = 600; lst = {}; Do[s = (a + b + c)/2; If[IntegerQ[s], area2 = s (s - a) (s - b) (s - c); If[0 < area2 && IntegerQ[Sqrt[area2]] && IntegerQ[Sqrt[Sqrt[area2]/s]], AppendTo[lst, Sqrt[area2]]]], {a, nn}, {b, a}, {c, b}]; Union[lst]
CROSSREFS
KEYWORD
nonn
AUTHOR
Michel Lagneau, Oct 20 2013
STATUS
approved