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A230166
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Terms of A222263 such that 2n/sigma(n) - 1 = 1/2^k, for some integer k.
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1
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1, 3, 15, 135, 819, 1365, 1485, 2295, 9009, 13923, 63855, 387387, 397575, 667275, 14381055, 16410735, 99558459, 271543725, 3145425129, 7096702977, 741585912975, 2148325363107, 4847048133291, 39206559148911, 53164445037705, 130468907286855, 1229923663366167
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OFFSET
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1,2
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COMMENTS
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For all n>1, sigma(n)>n, therefore 2n/sigma(n)-1 is always less than 1, i.e., k>0.
For k=1 to 11, the smallest known numbers to give 1/2^k are: 3, 15, 135, 2295, 1485, 1365, 63855, 16410735, 397575, 667275, 271543725.
For k=12 to 19, they are: unknown, 741585912975, unknown, 39206559148911, 2569480266942180207, 1712973775775070501, unknown, 299364435975778645966263.
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LINKS
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EXAMPLE
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a(1)=1 since 2*1/sigma(1)-1 = 2-1 = 1 = 1/2^0 is of the required form with k=0.
For n=2, 2*2/sigma(2)-1 = 4/3-1 = 1/3 is not of the form 1/2^k.
a(2)=3 since 2*3/sigma(3)-1 = 6/4-1 = 1/2 = 1/2^1 is of that form with k=1.
For a(3)=15, 2*15/sigma(15)-1 = 30/(1+3+5+15)-1 = 30/24 - 1 = 6/24 = 1/2^2 is of this form with k=2.
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PROG
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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