A230080 Sequence needed for the nonpositive powers of rho(11) = 2*cos(Pi/11) in terms of the power basis of the degree 5 number field Q(rho(11)). Coefficients of the first power.

0, 3, 5, 23, 73, 265, 920, 3245, 11385, 40018, 140574, 493911, 1735243, 6096533, 21419128, 75252674, 264387942, 928884046, 3263482673, 11465714843, 40282921096, 141527481021, 497233748352, 1746949771565, 6137623429414

Offset

0,2

Comments

The formula for the nonpositive powers of rho(11) := 2*cos(Pi/11) (the length ratio (smallest diagonal/side) in the regular 11-gon), when written in the power basis of the degree 5 algebraic number field Q(rho(11)) is: 1/rho(11)^n = A038342(n)*1 + a(n)*rho(11) - A230081(n)*rho(11)^2 - A069006(n-1)*rho(11)^3 + A038342(n-1)*rho(11)^4, n >= 0, with A069006(-1) = 0 = A038342(-1).

Links

Table of n, a(n) for n=0..24.

Index entries for linear recurrences with constant coefficients, signature (3,3,-4,-1,1).

Formula

G.f.: x*(3 - 4*x - x^2 + x^3)/(1 - 3*x - 3*x^2 + 4*x^3 + x^4 - x^5).

a(n) = 3*a(n-1) +3*a(n-2) -4*a(n-3) -a(n-4) +a(n-5) for n >= 0, with a(-5)=-3, a(-4)=a(-3)=a(-2)=0, a(-1)=1.

Example

1/rho(11)^4 = 146*1 + 73*rho(11) - 173*rho(11)^2 - 29*rho(11)^3  + 41*rho(11)^4 (approximately 0.07374164519).

Mathematica

LinearRecurrence[{3, 3, -4, -1, 1}, {0, 3, 5, 23, 73}, 30] (* Harvey P. Dale, May 19 2017 *)

Crossrefs

Cf. A038342, A069006, A230081.

Sequence in context: A027753 A066411 A153410 * A155778 A209028 A178068

Adjacent sequences: A230077 A230078 A230079 * A230081 A230082 A230083

Keyword

nonn,easy

Author

Wolfdieter Lang, Nov 04 2013

Status

approved