OFFSET
0,3
COMMENTS
Conjecture: (i) a(n) is always positive and divisible by Phi(n)^{Phi(n)}*sum_{d|n}Phi(d)*n/d, where Phi(n) is Euler's totient function.
(ii) For any composite number n, all prime divisors of a(n) are smaller than n.
It is easy to show that a(n) is divisible by Sum_{d|n} Phi(d)*n/d = Sum_{k=1..n} gcd(k,n), and a(p) = (p-1)^{p-1}*(2p-1) for any prime p.
LINKS
Alois P. Heinz, Table of n, a(n) for n = 0..388 (terms n = 1..100 from Zhi-Wei Sun)
EXAMPLE
a(1) = 1 since gcd(1-1,1) = 1.
MAPLE
a:= n-> LinearAlgebra[Determinant](Matrix(n, (i, j)-> igcd(i-j, n))):
seq(a(n), n=0..20); # Alois P. Heinz, Nov 03 2024
MATHEMATICA
a[n_]:=Det[Table[GCD[i-j, n], {i, 1, n}, {j, 1, n}]]
Table[a[n], {n, 1, 20}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Zhi-Wei Sun, Sep 06 2013
EXTENSIONS
a(0)=1 prepended by Alois P. Heinz, Nov 03 2024
STATUS
approved