

A228610


Numbers k such that the largest consecutive pair of prime(k)smooth integers is the same as the largest consecutive pair of prime(k1)smooth integers.


1




OFFSET

1,1


COMMENTS

For each such k = a(n), the smallest superparticular ratio R = m/(m1) such that R factors into primes less than or equal to prime(k) have all of these prime factors strictly less than prime(k).
k = a(n) here are the values of k that make a(k) = a(k1) in A002072 and also in A117581.


LINKS



EXAMPLE

For n = 1, k = a(1) = 9 gives prime(k) = 23 such that the largest consecutive pair of 23smooth integers, (11859210,11859211), is the same as the largest consecutive pair of prime(k1)smooth integers (19smooth integers).


CROSSREFS



KEYWORD

nonn,more,hard


AUTHOR



STATUS

approved



