OFFSET
1,1
COMMENTS
There exists a subsequence of infinite squares {36, 144, 196, 324, 441, 576, 676, 784, 1089, 1225, 1296, 1764,...} because the numbers of the form n = (p*q)^2 with p and q primes are in the sequence if p^2 + p*q + q^2 is prime (subsequence of A007645), and the numbers p^2, p*q and q^2 are the three possible semiprime divisors of n. This numbers of the sequence are 6^2, 14^2, 21^2, 26^2, 33^2, 35^2, 51^2, 69^2,...
The numbers of the form n = (p^a*q^v)^2 are also in the sequence => the sequence is infinite.
There exists a subsequence of numbers having three distinct prime divisors p, q and r such that p*q+q*r+r*p is prime (see A087054). This numbers are 30, 42, 66, 70, 78, 105, 114, ...
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000
EXAMPLE
30 is in the sequence because the semiprime divisors of 30 are 2*3, 2*5 and 3*5 and the sum 6+10+15 = 31 is a prime number.
MAPLE
with(numtheory):for n from 2 to 600 do:x:=divisors(n):n1:=nops(x): y:=factorset(n):n2:=nops(y):s1:=0:s2:=0:for i from 1 to n1 do: if bigomega(x[i])=2 then s1:=s1+x[i]:else fi:od: s2:=sum('y[i]', 'i'=1..n2):if type(s1, prime)=true then printf(`%d, `, n):else fi:od:
MATHEMATICA
semipSigma[n_] := DivisorSum[n, # &, PrimeOmega[#] == 2 &]; Select[Range[500], PrimeQ @ semipSigma[#] &] (* Amiram Eldar, May 10 2020 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Michel Lagneau, Jul 19 2013
STATUS
approved