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A218446
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a(n) = Sum_{k>=0} floor(n/(5*k + 3)).
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4
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0, 0, 0, 1, 1, 1, 2, 2, 3, 4, 4, 4, 5, 6, 6, 7, 8, 8, 10, 10, 10, 11, 11, 12, 14, 14, 15, 16, 17, 17, 18, 18, 19, 21, 21, 21, 23, 23, 24, 26, 27, 27, 28, 29, 29, 30, 31, 31, 34, 34, 34, 35, 36, 37, 39, 39, 41, 42, 43, 43, 44, 44, 44, 46, 47, 48, 50, 50, 51, 53, 53, 53, 56, 57, 57, 58, 59, 59, 62, 62, 63
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OFFSET
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0,7
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COMMENTS
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LINKS
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MATHEMATICA
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Accumulate[Table[Count[Divisors[n], _?(Mod[#, 5]==3&)], {n, 0, 90}]] (* Harvey P. Dale, Nov 08 2012 *)
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PROG
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(PARI) a(n)=sum(k=0, n, (n\(5*k+3)))
(Maxima) A218446[n]:=sum(floor(n/(5*k+3)), k, 0, n)$
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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