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A217993
Smallest k such that k^(2^n) + 1 and (k+2)^(2^n) + 1 are both prime.
1
2, 2, 2, 2, 74, 112, 2162, 63738, 13220, 54808, 3656570, 6992032, 125440, 103859114, 56414914, 87888966
OFFSET
0,1
COMMENTS
a(15)=87888966 but a(14) is unknown. - Jeppe Stig Nielsen, Mar 17 2018
The prime pair related to a(14) was found four days ago, and today double checking has proved that they are indeed the first occurrence for n=14. - Jeppe Stig Nielsen, May 02 2018
FORMULA
a(n) = A118539(n)-1. - Jeppe Stig Nielsen, Feb 27 2016
EXAMPLE
a(0) = 2 because 2^1+1 = 3 and 4^1+1 = 5 are prime;
a(1) = 2 because 2^2+1 = 5 and 4^2+1 = 17 are prime;
a(2) = 2 because 2^4+1 = 17 and 4^4+1 = 257 are prime;
a(3) = 2 because 2^8+1 = 257 and 4^8+1 = 65537 are prime.
MAPLE
for n from 0 to 5 do:ii:=0:for k from 2 by 2 to 10000 while(ii=0) do:if type(k^(2^n)+1, prime)=true and type((k+2)^(2^n)+1, prime)=true then ii:=1: printf ( "%d %d \n", n, k):else fi:od:od:
KEYWORD
nonn,hard,more
AUTHOR
Michel Lagneau, Oct 17 2012
EXTENSIONS
a(13) from Jeppe Stig Nielsen, Mar 17 2018
a(14) and a(15) from Jeppe Stig Nielsen, May 02 2018
STATUS
approved