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A216983
The integers sieved by 7, 5, 3, and 2.
0
7, 1, 2, 3, 2, 5, 3, 7, 2, 3, 5, 1, 3, 1, 7, 5, 2, 1, 3, 1, 5, 7, 2, 1, 3, 5, 2, 3, 7, 1, 5, 1, 2, 3, 2, 7, 3, 1, 2, 3, 5, 1, 7, 1, 2, 5, 2, 1, 3, 7, 5, 3, 2, 1, 3, 5, 7, 3, 2, 1, 5, 1, 2, 7, 2, 5, 3, 1, 2, 3, 7, 1, 3, 1, 2, 5, 2, 7, 3, 1, 5, 3, 2, 1, 7, 5, 2
OFFSET
1,1
COMMENTS
A number is tested for the following in order - the first test passed determines a(n):
Is n mod 7 == 1? If so, write 7.
Is n mod 5 == 1? If so, write 5.
Is n mod 3 == 1? If so, write 3.
Is n mod 2 == 1? If so, write 2.
Write 1.
Period 210. - Charles R Greathouse IV, Sep 22 2012
An example of an inverted sieve. Usually we would sieve 2, 3, 5, 7 which gives 2, 1, 2, 3, 2, 5, 2, 7, 2, 3, 2, 1. - Jon Perry, Sep 24 2012
EXAMPLE
4 is not 1 mod 7 or 1 mod 5 but is 1 mod 3, so a(4) = 3.
MATHEMATICA
Table[If[Mod[n, 7] == 1, 7, If[Mod[n, 5] == 1, 5, If[Mod[n, 3] == 1, 3, If[Mod[n, 2] == 1, 2, 1]]]], {n, 100}] (* T. D. Noe, Sep 25 2012 *)
Table[Which[Mod[n, 7]==1, 7, Mod[n, 5]==1, 5, Mod[n, 3]==1, 3, Mod[n, 2]==1, 2, True, 1], {n, 90}] (* Harvey P. Dale, Mar 04 2016 *)
PROG
(JavaScript) for (i=1; i<90; i++)
if (i%7==1) document.write("7, ");
else if (i%5==1) document.write("5, ");
else if (i%3==1) document.write("3, ");
else if (i%2==1) document.write("2, ");
else document.write("1, ");
(C++)
template <typename T> std::string PrintSequnce_A216983(const T &max)
{
std::string strSeq;
for(T i = 1; i < max; ++i)
{
if (i%7==1) strSeq+="7";
else if (i%5==1) strSeq+="5";
else if (i%3==1) strSeq+="3";
else if (i%2==1) strSeq+="2";
else strSeq+="1";
if(i<max-1)
strSeq+=", ";
}
return strSeq;
} // Martin Ettl, Oct 08 2012
CROSSREFS
Sequence in context: A134898 A371946 A176440 * A021588 A224998 A222216
KEYWORD
nonn,easy
AUTHOR
Jon Perry, Sep 21 2012
STATUS
approved