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A215582 The number of proper mergings of two n-antichains. 1
1, 3, 35, 1275, 154115, 71994363, 140595475715, 1133624776334235, 36970581556591250435, 4838797912961323412254203, 2535793883977350841761956006915, 5317221866238397002010248863448839835, 44602260230569982664472646479956459441496835, 1496585236610867406252010206465708857876795888774523 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
The number of proper mergings of an n-antichain and an m-antichain can be computed with the following formula: a(m,n)=Sum_{i+j+k=m} m!/(i!j!k!)*(-1)^k*(2^i+2^j-1)^n.
LINKS
FORMULA
a(n)=Sum_{i+j+k=n}{n!/(i!j!k!)*(-1)^k*(2^i+2^j-1)^n}.
limit n->infinity a(n)/(2^(n^2))=2 [From Vaclav Kotesovec, Aug 23 2012]
EXAMPLE
For n=1, the a(1)=3 proper mergings of two 1-antichains ({a},{}) and ({b},{}) are the following three posets: ({a,b},{}), ({a,b},{(a,b)}), ({a,b},{(b,a)}).
MATHEMATICA
Table[Sum[Sum[Sum[If[i+j+k==n, n!/(i!j!k!)*(-1)^k*(2^i+2^j-1)^n, 0], {i, 0, n}], {j, 0, n}], {k, 0, n}], {n, 0, 20}] (* Vaclav Kotesovec, Aug 23 2012 *)
CROSSREFS
Sequence in context: A062699 A012767 A279377 * A136525 A136556 A006098
KEYWORD
easy,nonn
AUTHOR
Henri Mühle, Aug 21 2012
STATUS
approved

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Last modified June 21 12:40 EDT 2024. Contains 373544 sequences. (Running on oeis4.)