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A213237
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Number of distinct values v satisfying v = sum of elements in S = product of elements in P for any partition of {1,...,n} into two sets S and P.
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2
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1, 0, 1, 0, 1, 1, 1, 1, 1, 2, 1, 2, 1, 3, 3, 2, 3, 1, 2, 3, 3, 2, 2, 4, 3, 5, 3, 2, 3, 3, 4, 4, 5, 1, 3, 2, 4, 4, 6, 3, 3, 2, 3, 4, 9, 3, 4, 9, 4, 3, 5, 4, 4, 4, 6, 6, 5, 5, 4, 7, 4, 8, 6, 4, 7, 3, 6, 5, 3, 4, 6, 5, 4, 6, 6, 5, 7, 4, 6, 9, 7, 6, 6, 8, 4, 7, 5
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OFFSET
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1,10
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LINKS
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EXAMPLE
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a(1) = 1: S={1}, P={}, v=1.
a(2) = 0: no partition of {1,2} satisfies the condition.
a(3) = 1: S={1,2}, P={3}, v=3.
a(10) = 2: three partitions of {1,2,...,10} into S and P satisfy v = Sum_{i:S} i = Product_{k:P} k but there are only two distinct values v: S={2,3,5,6,7,8,9}, P={1,4,10}, v=40; S={4,5,6,8,9,10}, P={1,2,3,7}, v=42; S={1,2,3,4,5,8,9,10}, P={6,7}, v=42.
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MAPLE
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b:= proc(n, s, p)
`if`(s=p, {s}, `if`(n<1, {}, {b(n-1, s, p)[],
`if`(s-n<p*n, {}, b(n-1, s-n, p*n))[]}))
end:
a:= n-> nops(b(n, n*(n+1)/2, 1)):
seq(a(n), n=1..100);
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MATHEMATICA
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b[n_, s_, p_] := b[n, s, p] = If[s == p, {s}, If[n < 1, {}, Union[b[n - 1, s, p], If[s - n < p n, {}, b[n - 1, s - n, p n]]]]];
a[n_] := Length[b[n, n(n+1)/2, 1]];
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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