1,1

Conjecture. On every interval [1,N] the numbers m for which A212990(m) less than or equal to Prime(m) are in majority.

Table of n, a(n) for n=1..53.

73 is in the sequence because 73 is the 21st prime, and A212990(21)=78 > 73.

Cf. A212990.

Sequence in context: A105126 A214643 A142038 * A269426 A224671 A044107

Adjacent sequences: A213044 A213045 A213046 * A213048 A213049 A213050

nonn

Vladimir Shevelev and Peter J. C. Moses, Jun 03 2012

approved