OFFSET
1,3
COMMENTS
Column 1 of A211904.
LINKS
R. H. Hardin, Table of n, a(n) for n = 1..75
FORMULA
Empirical: a(n) = (1/8)*n^4 + (1/4)*n^3 - (13/8)*n^2 + (5/4)*n + 1 for n>1.
Conjectures from Colin Barker, Jul 20 2018: (Start)
G.f.: x^2*(1 + 2*x + 3*x^2 - 4*x^3 + x^4) / (1 - x)^5.
a(n) = 5*a(n-1) - 10*a(n-2) + 10*a(n-3) - 5*a(n-4) + a(n-5) for n>6.
(End)
EXAMPLE
Some solutions for n=4:
.....0........0........0........0........0........0........0........0
....1.2......1.2......1.2......1.2......1.2......1.2......1.2......1.2
...3.4.5....3.4.5....3.4.0....2.3.4....3.4.5....3.4.3....3.4.5....0.3.4
..1.6.7.8..6.7.8.7..5.6.7.8..5.6.7.8..4.6.7.8..5.6.7.8..5.6.7.8..5.6.7.8
CROSSREFS
KEYWORD
nonn
AUTHOR
R. H. Hardin, Apr 25 2012
STATUS
approved