OFFSET
1,1
COMMENTS
Symmetry and 2 X 2 block sums zero implies that the diagonal x(i,i) are equal modulo 2 and x(i,j) = (x(i,i)+x(j,j))/2*(-1)^(i-j).
LINKS
R. H. Hardin, Table of n, a(n) for n = 1..210
FORMULA
Empirical: a(n) = 5*a(n-1) - 36*a(n-3) + 41*a(n-4) + 82*a(n-5) - 151*a(n-6) - 54*a(n-7) + 204*a(n-8) - 28*a(n-9) - 110*a(n-10) + 36*a(n-11) + 20*a(n-12) - 8*a(n-13).
Empirical g.f.: 2*x*(32 - 95*x - 202*x^2 + 765*x^3 + 308*x^4 - 2192*x^5 + 237*x^6 + 2761*x^7 - 876*x^8 - 1493*x^9 + 604*x^10 + 284*x^11 - 124*x^12) / ((1 - x)*(1 - 2*x)*(1 - x - x^2)*(1 - 2*x^2)*(1 - x - 2*x^2 + x^3)*(1 - 4*x^2 + 2*x^4)). - Colin Barker, Jul 16 2018
EXAMPLE
Some solutions for n=3:
.-3..4.-3..4....6.-1..6.-1...-5..1.-5..3....6..0..6.-3....4..1..1..1
..4.-5..4.-5...-1.-4.-1.-4....1..3..1..1....0.-6..0.-3....1.-6..4.-6
.-3..4.-3..4....6.-1..6.-1...-5..1.-5..3....6..0..6.-3....1..4.-2..4
..4.-5..4.-5...-1.-4.-1.-4....3..1..3.-1...-3.-3.-3..0....1.-6..4.-6
CROSSREFS
KEYWORD
nonn
AUTHOR
R. H. Hardin, Apr 06 2012
STATUS
approved