OFFSET
1,1
COMMENTS
For a guide to related sequences, see A205558.
LINKS
Robert Israel, Table of n, a(n) for n = 1..10000
EXAMPLE
The first six terms match these differences:
p(3)-p(1)=5-2=3=3*1
p(5)-p(1)=11-2=9=3*3
p(5)-p(3)=11-5=6=3*2
p(6)-p(4)=13-7=6=3*2
p(7)-p(1)=17-2=15=3*5
p(7)-p(3)=17-5=12=3*4
MAPLE
R:= NULL: N[0]:= 0: N[1]:= 0: N[2]:= 0: p:= 0:
for k from 1 to 30 do
p:= nextprime(p);
v:= p mod 3;
R:= R, k$N[v];
N[v]:= N[v]+1;
od:
R; # Robert Israel, Nov 18 2024
MATHEMATICA
s[n_] := s[n] = Prime[n]; z1 = 200; z2 = 80;
f[n_] := f[n] = Floor[(-1 + Sqrt[8 n - 7])/2];
Table[s[n], {n, 1, 30}] (* A000040 *)
u[m_] := u[m] = Flatten[Table[s[k] - s[j], {k, 2, z1}, {j, 1, k - 1}]][[m]]
Table[u[m], {m, 1, z1}] (* A204890 *)
v[n_, h_] := v[n, h] = If[IntegerQ[u[h]/n], h, 0]
w[n_] := w[n] = Table[v[n, h], {h, 1, z1}]
d[n_] := d[n] = Delete[w[n], Position[w[n], 0]]
c = 3; t = d[c] (* A205559 *)
k[n_] := k[n] = Floor[(3 + Sqrt[8 t[[n]] - 1])/2]
j[n_] := j[n] = t[[n]] - f[t][[n]] (f[t[[n]]] + 1)/2
Table[k[n], {n, 1, z2}] (* A205560 *)
Table[j[n], {n, 1, z2}] (* A205547 *)
Table[s[k[n]], {n, 1, z2}] (* A205673 *)
Table[s[j[n]], {n, 1, z2}] (* A205674 *)
Table[s[k[n]] - s[j[n]], {n, 1, z2}] (* A205557 *)
Table[(s[k[n]] - s[j[n]])/c, {n, 1, z2}] (* A205675 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Clark Kimberling, Jan 30 2012
STATUS
approved