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A201732
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a(n) = [x^n/n!] (1/x) * log( (n+1 - n*exp(x)) / (n+2 - (n+1)*exp(x)) ).
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1
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1, 2, 18, 386, 15150, 946082, 86148762, 10776331778, 1773210244230, 371367615732002, 96462262816769586, 30433572793375652738, 11463680237091180885150, 5081782052880868302982562, 2618864991559576227420716490, 1552537179057766207300655437826
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OFFSET
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0,2
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COMMENTS
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The function log((n+1 - n*exp(x))/(n+2 - (n+1)*exp(x))) equals the (n+1)-th iteration of log(1/(2-exp(x)), the e.g.f. of A000629 (with offset 1), where A000629(n) is the number of necklaces of partitions of n+1 labeled beads.
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LINKS
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FORMULA
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PROG
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(PARI) {a(n)=n!*polcoeff((1/x)*log((n+1 - n*exp(x+O(x^(n+2))))/(n+2 - (n+1)*exp(x+O(x^(n+2))))), n)}
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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