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A197702
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Smallest positive integer k such that n = +-1 +-3 +-... +-(2k-1) for some choice of +'s and -'s
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2
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1, 2, 3, 2, 5, 4, 3, 4, 3, 4, 5, 6, 5, 4, 5, 4, 5, 6, 5, 6, 7, 6, 5, 6, 5, 6, 7, 6, 7, 6, 7, 8, 7, 6, 7, 6, 7, 8, 7, 8, 7, 8, 7, 8, 9, 8, 7, 8, 7, 8, 9, 8, 9, 8, 9, 8, 9, 8, 9, 10, 9, 8, 9, 8, 9, 10, 9, 10, 9, 10, 9, 10, 9, 10, 9, 10, 11, 10, 9, 10, 9, 10, 11, 10, 11, 10, 11, 10, 11, 10, 11, 10, 11, 10, 11, 12, 11, 10, 11, 10
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OFFSET
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1,2
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COMMENTS
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Conjecture. Let SO(k) be the sum of the first k odd positive integers. Then a(n)=k if n=SO(k). Otherwise, choose k so that SO(k-1)<n<SO(k). Then if SO(k)-n=4, a(n)=k+2, else if SO(k)-n is odd then a(n)=k+1 else a(n)=k. (This has been verified for n up to 200.)
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LINKS
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EXAMPLE
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The sum of 3 terms 1 - 3 + 5 gives 3, but none of the 2-term sums 1+3, 1-3, -1+3, -1-3 gives 3, so a(3)=3.
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MAPLE
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b:= proc(n, i) option remember; (n=0 and i=0) or
abs(n)<=i^2 and (b(n-2*i+1, i-1) or b(n+2*i-1, i-1))
end:
a:= proc(n) local k;
for k from floor(sqrt(n)) while not b(n, k) do od; k
end:
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MATHEMATICA
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b[n_, i_] := b[n, i] = (n==0 && i==0) || Abs[n] <= i^2 && (b[n-2i+1, i-1] || b[n+2i-1, i-1]);
a[n_] := Module[{k}, For[k = Floor[Sqrt[n]], !b[n, k], k++]; k];
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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