0,3
Alois P. Heinz, Table of n, a(n) for n = 0..1000
a(n) = [x^(n^4)] 1/Product_{j>=0}(1-x^(4^j)).
a(2) = 6, because there are 6 partitions of 2^4=16 into powers of 4: [16], [4,4,4,4], [1,1,1,1,4,4,4], [1,1,1,1,1,1,1,1,4,4], [1,1,1,1,1,1,1,1,1,1,1,1,4], [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1].
Column k=4 of A196879.
Sequence in context: A156128 A052678 A052719 * A289392 A272688 A063965
Adjacent sequences: A196879 A196880 A196881 * A196883 A196884 A196885
nonn
Alois P. Heinz, Oct 07 2011
approved
