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A193279
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Number of distinct sums of distinct proper divisors of n.
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2
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0, 1, 1, 3, 1, 6, 1, 7, 3, 7, 1, 16, 1, 7, 7, 15, 1, 21, 1, 22, 7, 7, 1, 36, 3, 7, 7, 28, 1, 42, 1, 31, 7, 7, 7, 55, 1, 7, 7, 50, 1, 54, 1, 31, 27, 7, 1, 76, 3, 31, 7, 31, 1, 66, 7, 64, 7, 7, 1, 108, 1, 7, 29, 63, 7, 78, 1, 31, 7, 72, 1, 123, 1, 7, 31, 31
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OFFSET
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1,4
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COMMENTS
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a(n)=1 if and only if n is prime.
a(n)=n-1 if n is a power of 2.
a(n)=n if n is an even perfect number (is the converse true?)
Note: the count excludes an empty subset of proper divisors that would give 0 as a sum. - Antti Karttunen, Mar 07 2018
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LINKS
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MAPLE
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with(linalg): a:=proc(n) local dl, t: dl:=convert(numtheory[divisors](n) minus {n}, list): t:=nops(dl): return nops({seq(innerprod(dl, convert(2^t+i, base, 2)[1..t]), i=1..2^t-1)}): end: seq(a(n), n=1..76); # Nathaniel Johnston, Jul 23 2011
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MATHEMATICA
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a[n_] := Module[{d = Most @ Divisors[n], x}, Count[CoefficientList[Product[1 + x^i, {i, d}], x], _?(# > 0 &)] - 1]; Array[a, 100] (* Amiram Eldar, Jun 13 2020 *)
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PROG
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(PARI)
allocatemem(2^31);
powerset_without_emptyset(v) = { my(siz=(2^length(v))-1, pv=vector(siz)); for(i=1, siz, pv[i] = choosebybits(v, i)); pv; };
choosebybits(v, m) = { my(s=vector(hammingweight(m)), i=j=1); while(m>0, if(m%2, s[j] = v[i]; j++); i++; m >>= 1); s; };
A193279(n) = if(1==n, 0, my(pds = (divisors(n)[1..(numdiv(n)-1)]), subs = powerset_without_emptyset(pds)); length(vecsort(vector(#subs, i, vecsum(subs[i])) , , 8))); \\ Antti Karttunen, Mar 07 2018
(PARI)
\\ The following version does not need huge amounts of memory:
A193279(n) = if(1==n, 0, my(pds = (divisors(n)[1..(numdiv(n)-1)]), maxsum = vecsum(pds), sums = vector(maxsum), psetsiz = (2^length(pds))-1, k = 0, s); for(i=1, psetsiz, s = vecsum(choosebybits(pds, i)); if(!sums[s], k++; sums[s]++)); (k)); \\ Antti Karttunen, Mar 07 2018
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CROSSREFS
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Cf. A119347 (allows also n to be included in the sums).
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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