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 A192390 Numbers n such that number of primes in the range (2^n-sqrt(2^n), 2^n] is equal to number of primes in the range (2^n, 2^n+sqrt(2^n)]. 0
 1, 2, 6, 10, 21 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS a(6) > 60. Probably a finite sequence. [Charles R Greathouse IV, Jun 30 2011] LINKS EXAMPLE a(1)=1 because 2 in range (2^1-sqrt(1), 2^1]=(1, 2] and 3 in range (2^1, 2^1+sqrt(1)]=(2, 3]. a(3)=6 because 59, 61 in range (2^6-sqrt(2^6), 2^6]=(56, 64] and 67, 71 in range (2^6, 2^6+sqrt(2^6)]=(64, 72]. a(4)=10 because 997, 1009, 1013, 1019, 1021 in range (2^10-sqrt(2^10), 2^10]=(992, 1024] and 1031, 1033, 1039, 1049, 1051 in range (2^10, 2^10+sqrt(2^10)]=(1024, 1056]. PROG (PARI) ct(a, b)=sum(k=floor(a)+1, b, isprime(k)) is(n)=ct(2^n-sqrt(2^n-.5), 2^n)==ct(2^n, 2^n+sqrt(2^n+.5)) \\ Charles R Greathouse IV, Jul 19 2011 CROSSREFS Sequence in context: A025588 A009325 A308346 * A272967 A067716 A125518 Adjacent sequences: A192387 A192388 A192389 * A192391 A192392 A192393 KEYWORD nonn,more AUTHOR Juri-Stepan Gerasimov, Jun 29 2011 STATUS approved

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Last modified February 7 20:08 EST 2023. Contains 360129 sequences. (Running on oeis4.)