OFFSET
1,2
COMMENTS
Ulas and Ulas conjecture that all primes are here. The nonprime m are in A186892. See A186886 for the least number having m prime factors.
From Antti Karttunen, Dec 09 2025: (Start)
Apart from 2 and 3, all terms are congruent to 1 or 5 mod 6 (A007310). That there are no even terms after 2 is because B(2,x) = x and that there are no multiples of 3 after 3 follows because a Stern polynomial B(n,x) is a multiple of B(3,x) = (x+1) if and only if n is a multiple of 3. The proof follows below:
Starting from Stern Polynomial B(1,x) and arranging the polynomials in rows of lengths 2^k, computing them with the recurrence B(2*n,x) = x*B(n,x), B(2n+1,x) = B(n,x) + B(n+1,x), we have:
B(1,x) = 1
B(2,x) = x, B(3,x) = x + 1
B(4,x) = x^2, B(5,x) = 2x + 1, B(6,x) = x^2 + x, B(7,x) = x^2 + x + 1
B(8,x) = x^3, B(9,x) = x^2 + 2x + 1, etc.
Reducing these modulo (x+1), we obtain:
1,
-1, 0,
1, -1, 0, 1,
-1, 0, 1, -1, 0, 1, -1, 0,
...
and by induction it is easy to prove that the repeating pattern 1, -1, 0, 1, -1, 0, 1, -1, 0, ... persists forever. Note how B(2*n,x)%(x+1) = -(B(n,x)%(x+1)), as x%(x+1) = -1 and (x^2)%(x+1) = (-x)%(x+1) = 1, while on the other hand, for odd n, B(2n+1,x)%(x+1) = B(n,x)%(x+1) + B(n+1,x)%(x+1), where % stands for modulo operation. Note that similar induction shows that A002487(n) (which is the sum of coefficients of B(n, x)) is even if and only if n is a multiple of 3, and obviously, when we multiply any polynomial with (x+1), the sum of the coefficients of the product is even. (End)
LINKS
Charles R Greathouse IV, Table of n, a(n) for n = 1..10000
Maciej Ulas and Oliwia Ulas, On certain arithmetic properties of Stern polynomials, arXiv:1102.5109 [math.CO], 2011.
FORMULA
MATHEMATICA
ps[n_] := ps[n] = If[n<2, n, If[OddQ[n], ps[Quotient[n, 2]] + ps[Quotient[n, 2] + 1], x ps[Quotient[n, 2]]]];
selQ[n_] := IrreduciblePolynomialQ[ps[n]];
Join[{1}, Select[Range[200], selQ]] (* Jean-François Alcover, Nov 02 2018, translated from PARI *)
PROG
(PARI) ps(n)=if(n<2, n, if(n%2, ps(n\2)+ps(n\2+1), 'x*ps(n\2)))
is(n)=polisirreducible(ps(n)) \\ Charles R Greathouse IV, Apr 07 2015
CROSSREFS
KEYWORD
nonn
AUTHOR
T. D. Noe, Feb 28 2011
STATUS
approved
