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 A186145 Rank of n^2 when {i^2: i>=1} and {j^3>: j>=1} are jointly ranked with i^2 before j^3 when i^2=j^3.  Complement of A186146. 14
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 OFFSET 1,2 COMMENTS Suppose u,v,p,q are positive integers and 0<|d|<1. Let a(n)=n+floor(((u*n^p-d)/v)^(1/q)), b(n)=n+floor(((v*n^q+d)/u)^(1/p)). When the disjoint sets {u*i^p} and {v*j^q+d} are jointly ranked, the rank of u*n^p is a(n) and the rank of v*n^q+d is b(n).  Therefore a and b are a pair of complementary sequences.  Choosing d carefully serves as a basis for two types of adjusted joint rankings of non-disjoint sets {u*i^p} and {v*j^q}. First, if we place u*i^p before v*j^q whenever u*i^p=v*j^q, then with 0

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Last modified August 3 01:07 EDT 2021. Contains 346429 sequences. (Running on oeis4.)