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A185592
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a(n) = floor(n^(3/2))*floor(1 + n^(3/2))*floor(2 + n^(3/2))/6.
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1
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1, 4, 35, 120, 286, 560, 1140, 2024, 3654, 5456, 8436, 12341, 17296, 24804, 34220, 45760, 59640, 76076, 95284, 121485, 152096, 187460, 227920, 273819, 333375, 392084, 467180, 551300, 644956, 748660, 862924, 1004731, 1143135, 1313400, 1499784, 1703016, 1923825, 2162940, 2421090, 2699004, 3031864, 3391024, 3737581, 4149466, 4590551, 5061836, 5616324
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OFFSET
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1,2
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COMMENTS
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LINKS
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MATHEMATICA
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Table[Floor[n^(3/2)]*Floor[n^(3/2)+1]*Floor[n^(3/2)+2]/6, {n, 1, 80}]
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PROG
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(Magma) [Floor(n^(3/2))*Floor(n^(3/2)+1)*Floor(n^(3/2)+2)/6: n in [1..60]]; // Vincenzo Librandi, Sep 13 2011
(PARI) for(n=1, 50, print1(floor(n^(3/2))*floor(1+n^(3/2))*floor(2+n^(3/2))/6, ", ")) \\ G. C. Greubel, Jul 08 2017
(PARI) a(n) = my(f=sqrtnint(n^3, 2)); f*(f+1)*(f+2)/6; \\ Michel Marcus, Jul 08 2017
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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