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A185506 Accumulation array, T, of the natural number array A000027, by antidiagonals. 5
1, 3, 4, 7, 11, 10, 14, 23, 26, 20, 25, 42, 51, 50, 35, 41, 70, 88, 94, 85, 56, 63, 109, 140, 156, 155, 133, 84, 92, 161, 210, 240, 250, 237, 196, 120, 129, 228, 301, 350, 375, 374, 343, 276, 165, 175, 312, 416, 490, 535, 550, 532, 476, 375, 220, 231, 415, 558, 664, 735, 771, 770, 728, 639, 495, 286 (list; table; graph; refs; listen; history; text; internal format)
OFFSET

1,2

COMMENTS

Suppose that R={R(n,k) : n>=1, k>=1} is a rectangular array.  The accumulation array of R is given by T(n,k) = Sum_{R(i,j): 1<=i<=n, 1<=j<=k}. (See A144112.)

The formula for the integer T(n,k) has denominator 12.  The 2nd, 3rd, and 4th accumulation arrays of A000027 have formulas in which the denominators are 144, 2880, and 86400, respectively; see A185507, A185508, and A185509.

LINKS

G. C. Greubel, Table of n, a(n) for the first 50 antidiagonals, flattened

FORMULA

T(n,k) = k*n*(2*n^2 + 3*(k+1)*n + 2*k^2 - 3*k + 5)/12.

EXAMPLE

The natural number array A000027 starts with

  1, 2,  4,  7, ...

  3, 5,  8, 12, ...

  6, 9, 13, 18, ...

  ...

T(n,k) is the sum of numbers in the rectangle with corners at (1,1) and (n,k) of A000027, so that a corner of T is as follows:

   1,  3,   7,  14,  25,  41

   4, 11,  23,  42,  70, 109

  10, 26,  51,  88, 140, 210

  20, 50,  94, 156, 240, 350

  35, 85, 155, 250, 375, 535

MATHEMATICA

f[n_, k_]:=k*n*(2n^2+3(k+1)*n+2k^2-3k+5)/12;

TableForm[Table[f[n, k], {n, 1, 10}, {k, 1, 15}]]

Table[f[n-k+1, k], {n, 14}, {k, n, 1, -1}]//Flatten

CROSSREFS

Cf. A000027, A185507, A185508, A185509.

Cf. A004006 (row 1), A000292 (col 1), A051925 (col 2), A185505 (1st diagonal).

Sequence in context: A061447 A219188 A283428 * A328379 A080591 A291063

Adjacent sequences:  A185503 A185504 A185505 * A185507 A185508 A185509

KEYWORD

nonn,tabl

AUTHOR

Clark Kimberling, Jan 29 2011

STATUS

approved

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Last modified April 23 12:15 EDT 2021. Contains 343204 sequences. (Running on oeis4.)