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A182974
Numbers n for which A020652(n)/A038567(n) = A182972(n)/A182973(n).
4
1, 2, 7, 158, 1617, 6211, 8058, 16765, 69093, 465988, 5297983, 6546724, 18588348, 38244610, 204136352, 430712111, 2760559191, 100878516991, 440393924631
OFFSET
1,2
COMMENTS
Numerators of the matching fractions are given in A182975.
Denominators of the matching fractions are given in A182976.
The initial (zeroth) term of A038567 is ignored.
REFERENCES
S. Cook, Problem 511: An Enumeration Problem, Journal of Recreational Mathematics, Vol. 9:2 (1976-77), 137. Solution by the Problem Editor, JRM, Vol. 10:2 (1977-78), 122-123.
LINKS
Paul Yiu, Recreational Mathematics, 24.3.1 Appendix: Two enumerations of the rational numbers in (0,1), page 633.
EXAMPLE
a(1)=1, a(2)=2 and a(3)=7 because the 1st, 2nd and 7th fractions match in the following two sequences:
1/2, 1/3, 2/3, 1/4, 3/4, 1/5, 2/5, 3/5 ... (A020652/A038567)
1/2, 1/3, 1/4, 2/3, 1/5, 1/6, 2/5, 3/4 ... (A182972/A182973)
CROSSREFS
KEYWORD
nonn,more
AUTHOR
STATUS
approved