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A025487(j) and A025487(k) need not be distinct.
Because multiplying two members of A025487 always produces a member of A025487, the value of this function for all nonmembers of A025487 is 0.
Table of n, a(n) for n=1..65.
a(n) = A000005(A181815(n)).
36 has three different ordered factorizations into two members of A025487 (36 = 1*36 = 6*6 = 36*1). Therefore, since 36 = A025487(11), a(11) = 3.
Sequence in context: A249870 A145394 A179806 * A173997 A029143 A153846
Adjacent sequences: A182759 A182760 A182761 * A182763 A182764 A182765
Matthew Vandermast, Nov 30 2010