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A181642
Minimal sequence whose forwards van Eck transform is the sequence of prime numbers.
2
0, 1, 0, 2, 1, 3, 4, 0, 5, 6, 2, 7, 8, 9, 10, 1, 11, 12, 3, 13, 14, 15, 16, 4, 17, 18, 0, 19, 20, 21, 22, 5, 23, 24, 25, 26, 27, 28, 6, 29, 30, 2, 31, 32, 33, 34, 35, 36, 7, 37, 38, 39, 40, 8, 41, 42, 9, 43, 44, 45, 46, 10, 47, 48, 49, 50, 51, 52, 1, 53, 54
OFFSET
1,4
COMMENTS
At each step, the minimum available integer is used.
From Rémy Sigrist, Aug 12 2017: (Start)
a(n)=0 iff n belongs to A074271.
a(n)=1 iff n > 1 and n belongs to A259408.
For any k > 0, A064427(k) = least n such that a(n) = k-1.
(End)
LINKS
EXAMPLE
a(1)=0. Next 0 is at distance 2 (1st prime): a(3)=0.
a(2)=1. Next 1 is at distance 3 (2nd prime): a(5)=1.
a(3)=0. Next 0 is at distance 5 (3rd prime): a(8)=0.
For a(4), we can use neither 0 (distance 1 from previous 0 would lead to an incongruence) nor 1 (distance 1 from subsequent 1 would lead to another incongruence). Therefore we must use 2.
Next 2 must be at distance 7 (4th prime): a(11)=2. And so on.
MAPLE
P:=proc(q, h) local i, k, n, t, x; x:=array(1..h); for k from 1 to h do x[k]:=-1; od; x[1]:=0; i:=0; t:=0; for n from 1 to q do if isprime(n) then i:=i+1; if x[i]>-1 then x[i+n]:=x[i]; else t:=t+1; x[i]:=t; x[i+n]:=x[i]; fi; fi; od; seq(x[k], k=1..79); end: P(400, 500);
PROG
(PARI) a = vector(71, i, -1); u = 0; for (n=1, #a, if (a[n]<0, o = n; while (o <= #a, a[o] = u; o += prime(o)); u++); print1 (a[n] ", ")) \\ Rémy Sigrist, Aug 12 2017
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
EXTENSIONS
More terms from Rémy Sigrist, Aug 12 2017
STATUS
approved