|
|
A181628
|
|
Numbers k such that (2^k + 3^k)/13 is prime.
|
|
2
|
|
|
6, 10, 14, 22, 34, 38, 82, 106, 218, 334, 4414, 7246, 10118, 10942, 15898, 42422
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
All terms are of the form 2p, p prime.
The prime (2^4414 + 3^4414)/13 = 79300327387 ...611266 985181 has 2105 decimal digits.
|
|
LINKS
|
|
|
EXAMPLE
|
10 is in the sequence because (2^10+ 3^10)/13 = 60073/13 = 4621 is prime.
|
|
MAPLE
|
with(numtheory):for n from 1 to 4500 do: x:= (2^n + 3^n)/13:if floor(x)=x and
type(x, prime)=true then printf(`%d, `, n):else fi:od:
# alternative
Res:= NULL:
p:= 2:
while p < 6000 do
p:= nextprime(p);
if isprime((2^(2*p)+3^(2*p))/13) then Res:= Res, 2*p fi;
od:
|
|
PROG
|
(Python)
from sympy import isprime
def afind(limit, startk=1):
k = startk
pow2 = 2**k
pow3 = 3**k
for k in range(startk, limit+1):
q, r = divmod(pow2+pow3, 13)
if r == 0 and isprime(q):
print(k, end=", ")
pow2 *= 2
pow3 *= 3
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,more
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|