OFFSET
1,4
COMMENTS
The genus g(p) of a permutation p of {1,2,...,n} is defined by g(p) = (1/2)[n+1-z(p)-z(cp')], where p' is the inverse permutation of p, c = 234...n1 = (1,2,...,n), and z(q) is the number of cycles of the permutation q.
Row sums are A000108 (Catalan numbers).
T(n,1) = A000108(n-1) (n >= 1).
T(n,2) = A000108(n-1) (n >= 2).
T(n,3) = A000108(n-2) (n >= 3).
T(n,n) = A000108(n-2) (n >= 2).
A permutation p of {1,2,...,n} has genus 0 if and only if the cycle decomposition of p gives a noncrossing partition of {1,2,...,n} and each cycle of p is increasing (see Lemma 2.1 of the Dulucq-Simion reference).
REFERENCES
S. Dulucq and R. Simion, Combinatorial statistics on alternating permutations, J. Algebraic Combinatorics, 8, 1998, 169-191.
FORMULA
T(n,1)=c(n-1); T(n,k) = c(n-k+1)*c(k-2) if 2 <= k <= n, where c(j) = binomial(2j,j)/(j+1) = A000108(j) are the Catalan numbers.
G.f. = G(t,z) = t*z*C(z)+t^2*z*(C(z)-1)*C(tz), where C(z) = (1-sqrt(1-4*z))/(2z) is the Catalan function.
EXAMPLE
T(4,3)=2 because we have 3214=(13)(2)(4) and 3241=(134)(2).
Triangle starts:
1;
1, 1;
2, 2, 1;
5, 5, 2, 2;
14, 14, 5, 4, 5;
MAPLE
c := proc (n) options operator, arrow: binomial(2*n, n)/(n+1) end proc: a := proc (n, k) if k = 1 then c(n-1) elif k <= n then c(n-k+1)*c(k-2) else 0 end if end proc: for n to 11 do seq(a(n, k), k = 1 .. n) end do; # yields sequence in triangular form
MATHEMATICA
t[n_, 1] := CatalanNumber[n-1]; t[n_, k_] := CatalanNumber[n-k+1] * CatalanNumber[k-2]; Table[t[n, k], {n, 1, 11}, {k, 1, n}] // Flatten (* Jean-François Alcover, Jul 10 2013 *)
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Emeric Deutsch, May 31 2010
STATUS
approved