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A177886
The number of isomorphism classes of Latin quandles (a.k.a. left distributive quasigroups) of order n.
13
1, 0, 1, 1, 3, 0, 5, 2, 8, 0, 9, 1, 11, 0, 5, 9, 15, 0, 17, 3, 7, 0, 21, 2, 34, 0, 62, 7, 27, 0, 29, 8, 11, 0, 15, 9, 35, 0, 13, 6, 39, 0, 41, 9, 36, 0, 45
OFFSET
1,5
COMMENTS
A quandle is Latin if its multiplication table is a Latin square. A Latin quandle may be described as a left (or right) distributive quasigroup. Sherman Stein (see reference below) proved that a left distributive quasigroup of order n exists if and only if n is not of the form 4k + 2.
LINKS
W. E. Clark, M. Elhamdadi, M. Saito, and T. Yeatman, Quandle Colorings of Knots and Applications, arXiv preprint arXiv:1312.3307 [math.GT], 2013-2014.
G. Ehrman, A. Gurpinar, M. Thibault, and D. Yetter, Some Sharp Ideas on Quandle Construction
A. Hulpke, D. Stanovský, and P. Vojtěchovský, Connected quandles and transitive groups, arXiv:1409.2249 [math.GR], 2014.
S. Nelson, A polynomial invariant of finite quandles, arXiv:math/0702038 [math.QA], 2007.
S. K. Stein, On the Foundations of Quasigroups, Transactions of American Mathematical Society, 85 (1957), 228-256.
Leandro Vendramin, On the classification of quandles of low order, arXiv:1105.5341 [math.GT], 2011-2012.
Leandro Vendramin and Matías Graña, Rig, a GAP package for racks and quandles.
EXAMPLE
a(2) = 0 since the only quandle of order 2 has multiplication table with rows [1,1] and [2,2].
PROG
(GAP) # (using the Rig package)
LoadPackage("rig");
a:=[1, 0];;
Print(1, ", ");
Print(0, ", ");
for n in [3..35] do
a[n]:=0;
for i in [1..NrSmallQuandles(n)] do
if IsLatin(SmallQuandle(n, i)) then
a[n]:=a[n]+1;
fi;
od;
Print(a[n], ", ");
od; # W. Edwin Clark, Nov 26 2011
CROSSREFS
KEYWORD
nonn,more,changed
AUTHOR
W. Edwin Clark, Dec 14 2010
EXTENSIONS
Added fact due to S. K. Stein that a(4k+2) = 0 and a reference to Stein's paper.
a(11)-a(35) from W. Edwin Clark, Nov 26 2011
Links to the rig Gap package by W. Edwin Clark, Nov 26 2011
a(36)-a(47) by David Stanovsky, Oct 01 2014
STATUS
approved