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A176646
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a(n) is the number of convex pentagons in an n-triangular net.
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2
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0, 0, 3, 21, 78, 216, 498, 1014, 1884, 3264, 5349, 8379, 12642, 18480, 26292, 36540, 49752, 66528, 87543, 113553, 145398, 184008, 230406, 285714, 351156, 428064, 517881, 622167, 742602, 880992, 1039272, 1219512, 1423920, 1654848, 1914795, 2206413, 2532510, 2896056
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OFFSET
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1,3
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COMMENTS
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See P(n) in Theorem 2.1, p.2 of Zhu.
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LINKS
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FORMULA
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a(n) = (1/320)*(12*n^5 - 10*n^4 - 60*n^3 + 40*n^2 + 48*n - 15 + 15*(-1)^n).
a(2*n+1) = n*(n+1)*(12*n^3 + 13*n^2 - 8*n - 2)/10.
a(2*n) = n*(4*n-3)*(3*n+1)*(n-1)*(n+1)/10.
G.f.: 3*x^3*(1 + 2*x)/((1 + x)*(1 - x)^6).
E.g.f.: (1/320)*(15*exp(-x) - (15 -30*x +30*x^2 -180*x^3 -110*x^4 -12*x^5)*exp(x)). (End)
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MAPLE
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A176646:= n-> (12*n^5 -10*n^4 -60*n^3 +40*n^2 +48*n -15 +15*(-1)^n)/320;
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MATHEMATICA
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LinearRecurrence[{5, -9, 5, 5, -9, 5, -1}, {0, 0, 3, 21, 78, 216, 498}, 40] (* Harvey P. Dale, Jan 14 2015 *)
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PROG
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(Magma) [(1/320)*(12*n^5 -10*n^4 -60*n^3 +40*n^2 +48*n -15 +15*(-1)^n): n in [1..40]]; // G. C. Greubel, Jul 02 2021
(Sage) [(1/320)*(12*n^5 -10*n^4 -60*n^3 +40*n^2 +48*n -15 +15*(-1)^n) for n in (1..40)] # G. C. Greubel, Jul 02 2021
(PARI) f(k) = (12*k^5 + 25*k^4 + 5*k^3 - 10*k^2 - 2*k)/10;
g(k) = (12*k^5 - 5*k^4 - 15*k^3 + 5*k^2 + 3*k)/10;
a(n) = if (n%2, f((n-1)/2), g(n/2)); \\ Michel Marcus, Jul 04 2021
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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