

A176360


a(n) = quadrant of unit circle corresponding to n radians.


0



1, 2, 2, 3, 4, 4, 1, 2, 2, 3, 4, 4, 1, 1, 2, 3, 3, 4, 1, 1, 2, 3, 3, 4, 4, 1, 2, 2, 3, 4, 4, 1, 2, 2, 3, 3, 4, 1, 1, 2, 3, 3, 4, 1, 1, 2, 2, 3, 4, 4, 1, 2, 2, 3, 4, 4, 1, 1, 2, 3, 3, 4, 1, 1, 2, 3, 3, 4, 4, 1, 2, 2, 3, 4, 4, 1, 2, 2, 3, 3, 4, 1, 1, 2, 3, 3, 4, 1, 1, 2, 2, 3, 4, 4, 1, 2, 2, 3, 4, 4, 1, 1, 2, 3, 3
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OFFSET

1,2


COMMENTS

Radians are the natural measure of angle. Quadrants (1 through 4) determine the signs of (x,y); of (cos x, sin x); and are ubiquitous.
Thereby it is "interesting" to consider which quadrant contains successively larger integer radian measure.


LINKS

Table of n, a(n) for n=1..105.


FORMULA

a(n) = 1 + {floor [2*n/Pi] modulo(4)}.  Adam Helman, Apr 20 2010


EXAMPLE

a(11) is very nearly 7 quadrants as Pi is nearly exactly 22/7.
Indeed, 11 radians lies just 4.4 milliradian (0.25 degree) within the 4th quadrant.


MATHEMATICA

Table[Mod[1+Floor[(2n)/Pi], 4], {n, 120}]/.(0>4) (* Harvey P. Dale, Apr 09 2020 *)


PROG

From Adam Helman, Apr 20 2010: (Start)
(Other) # a(n) = 1 + {floor [2*n/pi] modulo(4)}
# Ruby code by Andy Martin
# Overkill here, 4 places properly gives first 200 terms.
t = 2000000000000000000000000000000000000000000000000000000000000000000
pi = 3141592653589793238462643383279502884197169399375105820974944592307
(1..200).each{ n print "#{1 + ((n*t)/pi)%4}, "}
print "\b \n"
(End)


CROSSREFS

Sequence in context: A171830 A071506 A125920 * A185068 A078664 A328388
Adjacent sequences: A176357 A176358 A176359 * A176361 A176362 A176363


KEYWORD

nonn,easy


AUTHOR

Adam Helman, Apr 15 2010, Apr 20 2010


STATUS

approved



