|
|
A176223
|
|
Natural numbers k which give a prime by the function f(k) = 2 * k + 13 for at least two iterations.
|
|
3
|
|
|
2, 5, 8, 17, 23, 35, 38, 47, 50, 68, 77, 80, 107, 110, 113, 140, 152, 170, 218, 227, 233, 245, 248, 278, 287, 317, 320, 332, 353, 365, 380, 392, 407, 437, 458, 467, 485, 500, 518, 542, 575, 590, 602, 605, 623, 635, 638, 710, 740, 743, 770, 803, 827, 842
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
n, p = f(k) = 2 * k + 13, q = f(f(k)) = 4 * k + 39; p and q to be primes.
List of (k,p,q):
(2,17,47) (5,23,59) (8,29,71) (17,47,107) (23,59,131)
(35,83,179) (38,89,191) (47,107,227) (50,113,239) (68,149,311)
(77,167,347) (80,173,359) (107,227,467) (110,233,479) (113,239,491)
(140,293,599) (152,317,647) (170,353,719) (218,449,911) (227,467,947)
(233,479,971) (245,503,1019) (248,509,1031) (278,569,1151) (287,587,1187)
(317,647,1307) (320,653,1319) (332,677,1367) (353,719,1451) (365,743,1499)
|
|
LINKS
|
|
|
EXAMPLE
|
2 * 2 + 13 = 17 = prime(7), 4 * 2 + 39 = 47 = prime(15), 2 is first term.
2 * 5 + 13 = 23 = prime(9), 4 * 5 + 39 = 59 = prime(17), 5 is 2nd term.
|
|
MATHEMATICA
|
k13Q[n_]:=AllTrue[Rest[NestList[2#+13&, n, 2]], PrimeQ]; Select[Range[ 1000], k13Q] (* Requires Mathematica version 10 or later *) (* Harvey P. Dale, Nov 20 2020 *)
|
|
PROG
|
(PARI) isok(n) = isprime(p=2*n+13) && isprime(2*p+13) \\ Michel Marcus, Jun 28 2013
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
Eva-Maria Zschorn (e-m.zschorn(AT)zaschendorf.km3.de), Apr 12 2010
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|