login
A174067
Triangle, row sums = A000041 starting (1, 2, 3, 5, 7, ...); derived from finite differences of p(x) = A(x)*A(x^2) = B(x)*B(x^3) = C(x)*C(x^4) = ...
4
1, 1, 1, 2, 0, 1, 3, 1, 0, 1, 4, 1, 1, 0, 1, 5, 2, 2, 1, 0, 1, 7, 2, 3, 1, 1, 0, 1, 9, 4, 3, 3, 1, 1, 0, 1, 12, 5, 5, 3, 3, 0, 1, 0, 1, 15, 8, 6, 5, 3, 2, 1, 1, 0, 1, 19, 10, 9, 6, 5, 2, 2, 1, 1, 0, 1, 25, 13, 12, 10, 5, 5, 2, 2, 1, 1, 0, 1, 31, 17, 16, 12, 9, 5, 4, 2, 2, 1, 1, 0, 1
OFFSET
1,4
COMMENTS
Row sums = A000041 starting with offset 1: (1, 2, 3, 5, 7, 11, ...).
FORMULA
Given an array of rows satisfying p(x) = A(x)*A(x^2) = row 1 = A174065; row = 2 A174068 satisfying p(x) = B(x)*B(x^3); row 3 satisfies p(x) = C(x)*C(x^4), ... and so on; take finite differences from the top, becoming rows of triangle A174067.
EXAMPLE
First few rows of the array:
1, 1, 1, 2, 3, 4, 5, 7, 9, 12, 15, 19, ... = A174065
1, 1, 2, 2, 4, 5, 7, 9, 13, 17, 23, 29, ... = A174068
1, 1, 2, 3, 4, 6, 9, 12, 16, 22, 29, 38, ... satisfies p(x) = C(x)*C(x^4)
1, 1, 2, 3, 5, 6, 10, 13, 19, 25, 34, 44, ... analogous for k=5
1, 1, 2, 3, 5, 7, 10, 14, 20, 28, 37, 49, ..................k=6
1, 1, 2, 3, 5, 7, 11, 14, 21, 28, 39, 51, ..................k=7
1, 1, 2, 3, 5, 7, 11, 15, 21, 29, 40, 53, ..................k=8
1, 1, 2, 3, 5, 7, 11, 15, 22, 29, 41, 54, ..................k=9
1, 1, 2, 3, 5, 7, 11, 15, 22, 30, 41, 55, ..................k=10
...
Finally, take finite differences from the top, deleting the first 1, to obtain triangle A174067:
1;
1, 1;
2, 0, 1;
3, 1, 0, 1;
4, 1, 1, 0, 1;
5, 2, 2, 1, 0, 1;
7, 2, 3, 1, 1, 0, 1;
9, 4, 3, 3, 1, 1, 0, 1;
12, 5, 5, 3, 3, 0, 1, 0, 1;
15, 8, 6, 5, 3, 2, 1, 1, 0, 1;
19, 10, 9, 6, 5, 2, 2, 1, 1, 0, 1;
25, 13, 12, 10, 5, 5, 2, 2, 1, 1, 0, 1;
31, 17, 16, 12, 9, 5, 4, 2, 2, 1, 1, 0, 1;
38, 24, 20, 18, 11, 8, 5, 4, 2, 2, 1, 1, 0, 1;
...
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Gary W. Adamson, Mar 06 2010
STATUS
approved