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A169942
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Number of Golomb rulers of length n.
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49
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1, 1, 3, 3, 5, 7, 13, 15, 27, 25, 45, 59, 89, 103, 163, 187, 281, 313, 469, 533, 835, 873, 1319, 1551, 2093, 2347, 3477, 3881, 5363, 5871, 8267, 9443, 12887, 14069, 19229, 22113, 29359, 32229, 44127, 48659, 64789, 71167, 94625, 105699, 139119, 151145, 199657
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OFFSET
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1,3
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COMMENTS
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Wanted: a recurrence. Are any of A169940-A169954 related to any other entries in the OEIS?
Leading entry in row n of triangle in A169940. Also the number of Sidon sets A with min(A) = 0 and max(A) = n. Odd for all n since {0,n} is the only symmetric Golomb ruler, and reversal preserves the Golomb property. Bounded from above by A032020 since the ruler {0 < r_1 < ... < r_t < n} gives rise to a composition of n: (r_1 - 0, r_2 - r_1, ... , n - r_t) with distinct parts. - Tomas Boothby, May 15 2012
Also the number of compositions of n such that every restriction to a subinterval has a different sum. This is a stronger condition than all distinct consecutive subsequences having a different sum (cf. A325676). - Gus Wiseman, May 16 2019
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LINKS
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FORMULA
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EXAMPLE
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For n=2, there is one Golomb Ruler: {0,2}. For n=3, there are three: {0,3}, {0,1,3}, {0,2,3}. - Tomas Boothby, May 15 2012
The a(1) = 1 through a(8) = 15 compositions such that every restriction to a subinterval has a different sum:
(1) (2) (3) (4) (5) (6) (7) (8)
(12) (13) (14) (15) (16) (17)
(21) (31) (23) (24) (25) (26)
(32) (42) (34) (35)
(41) (51) (43) (53)
(132) (52) (62)
(231) (61) (71)
(124) (125)
(142) (143)
(214) (152)
(241) (215)
(412) (251)
(421) (341)
(512)
(521)
(End)
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MATHEMATICA
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Table[Length[Select[Join@@Permutations/@IntegerPartitions[n], UnsameQ@@ReplaceList[#, {___, s__, ___}:>Plus[s]]&]], {n, 15}] (* Gus Wiseman, May 16 2019 *)
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PROG
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(Sage)
R = QQ['x']
return sum(1 for c in cartesian_product([[0, 1]]*n) if max(R([1] + list(c) + [1])^2) == 2)
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CROSSREFS
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Cf. A000079, A103295, A103300, A108917, A143824, A325466, A325545, A325676, A325678, A325679, A325683, A325686.
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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