OFFSET
1,1
COMMENTS
A138100 counts upwards in blocks of 2*k^2 numbers, restarting from 1,5,21,57,.. = A166464(k-1) = (2*k+1)*(2*k^2-4*k+3)/3, k>=1.
A168142 counts downwards in blocks of 2*k^2 numbers, restarting from 2*k^2, k>=1.
In consequence, the sequence here contains 2*k^2 copies of the number 1+2*k*(1+2*k^2)/3 = 1+A035597(k), k>=1,
CROSSREFS
KEYWORD
nonn,less
AUTHOR
Paul Curtz, Nov 21 2009
EXTENSIONS
Edited by R. J. Mathar, Feb 15 2010
STATUS
approved