

A166511


Comma numbers: n=concat(a,b) occurs in the sequence S[0]=a, S[1]=b, S[k+1]=S[k]+10*last_digit(S[k1])+first_digit(S[k]).


4



10, 20, 30, 40, 50, 60, 70, 80, 90, 109, 123, 148, 160, 163, 185, 198, 199, 241, 340, 362, 398, 422, 423, 444, 522, 540, 541, 550, 564, 597, 621, 622, 667, 683, 693, 724, 769, 770, 780, 806, 811, 835, 842, 888, 972, 1023, 1044, 1053, 1054, 1116, 1146, 1177
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OFFSET

1,1


COMMENTS

A comma number n is the concatenation of numbers a,b (no leading zeros allowed) which occurs ("again") in the comma sequence S = S(a,b) defined by S[0]=a, S[1]=b, S[n+1] = S[n] + 10*last_digit(S[n1]) + first_digit(S[n]), i.e., add to a given term the number formed by the two digits surrounding the preceding comma.
The sequence S is infinite and straightforward to compute, in contrast to the implicitly defined terms of A121805.
The sequence S(a,b) is strictly increasing, unless a=0 (mod 10) and b=0 (which implies n=0 (mod 100)), in which case all following terms are zero.


LINKS



EXAMPLE

a(1)=10 is in the sequence, because splitting 10 into (1,0) gives the sequence S(1,0) = 1, 0, 0+10=10, 10+01=11, 11+01=12, 12+11=23,... which contains 10.
a(10)=109 is in the sequence, because splitting 109 into (10,9) gives the sequence S(10,9) = 10, 9, 9+09=18, 18+91=109, 109+81=190,... which contains 109.
108 is not in the sequence since S(10,8) does not contain 108 and it is not allowed to split 108 > 1,08 > S(1,08).


PROG

(PARI) {for(n=1, 1e4, /*iscomma(n)=*/for(d=1, #Str(n)1, my( a=n\10^d, b=n%10^d ); b<10^(d1) & (d>1  a%10==0) & next; while(n > b=10*(a%10)+b\10^(#Str(b)1)+a=b, ); b>n & next; /*return(1)*/ print1(n", "); break))}


CROSSREFS



KEYWORD

base,nonn


AUTHOR



STATUS

approved



