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A165424
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a(1) = 1, a(2) = 6, a(n) = product of the previous terms for n >= 3.
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5
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OFFSET
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1,2
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LINKS
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FORMULA
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a(1) = 1, a(2) = 6, a(n) = Product_{i=1..n-1} a(i), n >= 3.
a(1) = 1, a(2) = 6, a(n) = A000400(2^(n-3)) = 6^(2^(n-3)), n >= 3.
a(1) = 1, a(2) = 6, a(3) = 6, a(n) = (a(n-1))^2, n >= 4.
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MATHEMATICA
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a[1]:= 1; a[2]:= 6; a[n_]:= Product[a[j], {j, 1, n-1}]; Table[a[n], {n, 1, 12}] (* G. C. Greubel, Oct 19 2018 *)
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PROG
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(PARI) {a(n) = if(n==1, 1, if(n==2, 6, prod(j=1, n-1, a(j))))};
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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