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 A164578 Integers of the form (k+1)*(2k+1)/12. 3
 10, 23, 65, 94, 168, 213, 319, 380, 518, 595, 765, 858, 1060, 1169, 1403, 1528, 1794, 1935, 2233, 2390, 2720, 2893, 3255, 3444, 3838, 4043, 4469, 4690, 5148, 5385, 5875, 6128, 6650, 6919, 7473, 7758, 8344, 8645, 9263, 9580, 10230, 10563, 11245, 11594 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS This can also be defined as integer averages of the first k halved squares, 1^2/2, 2^2/2, 3^2/2,... , 3^k/2, because sum_{j=1..k} j^2/2 = k*(k+1)*(2k+1)/12. The generating k are in A168489. LINKS Colin Barker, Table of n, a(n) for n = 1..1000 Index entries for linear recurrences with constant coefficients, signature (1,2,-2,-1,1). FORMULA a(n) = +a(n-1) +2*a(n-2) -2*a(n-3) -a(n-4) +a(n-5). G.f. x*(-10-13*x-22*x^2-3*x^3) / ((1+x)^2*(x-1)^3). - R. J. Mathar, Jan 25 2011 From Colin Barker, Jan 26 2016: (Start) a(n) = (24*n^2+6*n-(-1)^n*(8*n+1)+1)/4. a(n) = (12*n^2-n)/2 for n even. a(n) = (12*n^2+7*n+1)/2 for n odd. (End) MATHEMATICA s=0; lst={}; Do[a=(s+=(n^2)/2)/n; If[Mod[a, 1]==0, AppendTo[lst, a]], {n, 2*6!}]; lst Select[Table[((n+1)(2n+1))/12, {n, 300}], IntegerQ] (* or *) LinearRecurrence[ {1, 2, -2, -1, 1}, {10, 23, 65, 94, 168}, 60] (* Harvey P. Dale, Jun 14 2017 *) PROG (PARI) Vec(x*(10+13*x+22*x^2+3*x^3)/((1-x)^3*(1+x)^2) + O(x^100)) \\ Colin Barker, Jan 26 2016 CROSSREFS Cf. A078617, A078618, A154293, A164576, A164577. Sequence in context: A316093 A262485 A219940 * A219472 A196890 A219383 Adjacent sequences:  A164575 A164576 A164577 * A164579 A164580 A164581 KEYWORD nonn,easy AUTHOR Vladimir Joseph Stephan Orlovsky, Aug 16 2009 STATUS approved

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Last modified September 23 11:24 EDT 2021. Contains 347612 sequences. (Running on oeis4.)