OFFSET
0,2
COMMENTS
Coordination sequence for a chain of hexagons joined by single edges. - N. J. A. Sloane, Nov 21 2019
LINKS
G. C. Greubel, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (1,-1,1).
FORMULA
a(n) = 3*b(n) unless n=0 where b(n) is multiplicative with b(2) = 4/3, b(2^e) = 2/3 if e>1, b(p^e) = 1 if p>2.
Euler transform of length 4 sequence [3, -2, -1, 1].
Moebius transform is length 4 sequence [3, 1, 0, -2].
a(n) = a(-n) for all n in Z. a(n+4) = a(n) unless n=0 or n=-4. a(4*n) == 2 unless n=0. a(2*n + 1) = 3. a(4*n + 2) = 4.
G.f.: -1 + 3 / (1 - x) - 1 / (1 + x^2).
G.f.: (1+x)*(1+x+x^2)/((1-x)*(1+x^2)). - N. J. A. Sloane, Nov 21 2019
EXAMPLE
G.f. = 1 + 3*x + 4*x^2 + 3*x^3 + 2*x^4 + 3*x^5 + 4*x^6 + 3*x^7 + 2*x^8 + ...
MATHEMATICA
a[ n_] := - Boole[n == 0] + 3 - If[ EvenQ[n], (-1)^(n/2), 0];
CoefficientList[Series[(1+3*x+4*x^2+3*x^3+x^4)/(1-x^4), {x, 0, 150}], x] (* G. C. Greubel, Sep 26 2018 *)
PROG
(PARI) {a(n) = -(n==0) + 3 - if( n%2 == 0, (-1)^(n/2), 0)};
(PARI) x='x+O('x^150); Vec((1+3*x+4*x^2+3*x^3+x^4)/(1-x^4)) \\ G. C. Greubel, Sep 26 2018
(Magma) m:=150; R<x>:=PowerSeriesRing(Integers(), m); Coefficients(R!((1+3*x+4*x^2+3*x^3+x^4)/(1-x^4))); // G. C. Greubel, Sep 26 2018
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Michael Somos, Aug 13 2009
STATUS
approved