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A162892 Integers n such that the century defined by the interval [100n+1,100n+100] (i.e., the (n+1)-st century) contains exactly three Ormiston prime pairs. 1
651507, 1057749, 1263729, 1666162, 2527374, 3620083, 3850824, 4925140, 5418973, 8255451, 8300166, 8318772, 8389776, 9829099, 10876176, 11419227, 12195316, 14241925, 15170550, 15864637, 15876420, 16868593, 16892233, 17123505, 18032409 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

Ormiston pairs must be of form (100n+13,100n+31), (100n+37,100n+73), (100n+79,100n+97).

There cannot be more than three Ormiston prime pairs in a century.

LINKS

Table of n, a(n) for n=1..25.

PROG

(PARI) is(n)=isprime(100*n+13) && nextprime(100*n+17)==100*n+31 && isprime(100*n+37) && nextprime(100*n+39)==100*n+73 && isprime(100*n+79) && nextprime(100*n+81)==100*n+97 \\ Charles R Greathouse IV, Mar 07 2016

CROSSREFS

Cf. A162893.

Sequence in context: A058327 A234160 A105002 * A232675 A321064 A186614

Adjacent sequences:  A162889 A162890 A162891 * A162893 A162894 A162895

KEYWORD

base,nonn

AUTHOR

Ray Chandler and Ki Punches, Jul 16 2009

STATUS

approved

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Last modified January 20 09:55 EST 2022. Contains 350471 sequences. (Running on oeis4.)