A162892 Integers n such that the century defined by the interval [100n+1,100n+100] (i.e., the (n+1)-st century) contains exactly three Ormiston prime pairs.

651507, 1057749, 1263729, 1666162, 2527374, 3620083, 3850824, 4925140, 5418973, 8255451, 8300166, 8318772, 8389776, 9829099, 10876176, 11419227, 12195316, 14241925, 15170550, 15864637, 15876420, 16868593, 16892233, 17123505, 18032409

Offset

1,1

Comments

Ormiston pairs must be of form (100n+13,100n+31), (100n+37,100n+73), (100n+79,100n+97).

There cannot be more than three Ormiston prime pairs in a century.

Links

Table of n, a(n) for n=1..25.

Prog

(PARI) is(n)=isprime(100*n+13) && nextprime(100*n+17)==100*n+31 && isprime(100*n+37) && nextprime(100*n+39)==100*n+73 && isprime(100*n+79) && nextprime(100*n+81)==100*n+97 \\ Charles R Greathouse IV, Mar 07 2016

Crossrefs

Cf. A162893.

Sequence in context: A058327 A234160 A105002 * A232675 A321064 A186614

Adjacent sequences: A162889 A162890 A162891 * A162893 A162894 A162895

Keyword

base,nonn

Author

Ray Chandler and Ki Punches, Jul 16 2009

Status

approved