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A161557
a(n) = (n+1)*A000521(n), n>(-1).
1
1, 744, 393768, 64481280, 3457199880, 101229281280, 1999215843600, 29764163100672, 357255952575480, 3613417979904000, 31764402297844200, 248241326405529600, 1754542937994231528, 11366078355915079680, 68208141565173995280
OFFSET
-1,2
COMMENTS
[Mathworld]: "Lehmer(1942) showed that (n+1)*C(n) == 0 mod 24 for n >= 1" Cf. A161395: (0, 31, 16407, 2686720, 144049995,...) = ((n+1)*A000521(n)) / 24.
LINKS
Eric Weisstein's World of Mathematics, j-Function
FORMULA
a(n) = (n+1)*A000521(n), n > -1.
a(n) ~ n^(1/4) * exp(4*Pi*sqrt(n)) / sqrt(2). - Vaclav Kotesovec, Mar 06 2018
EXAMPLE
a(2) = 64481280 = 3*A000521(2) = 3*21493760; such that 64481280 == 0 mod 24, where 64481280 / 24 = 2686720 = A161395(2).
MATHEMATICA
a[n_] := With[{tau = Log[q]/(2 Pi I)}, SeriesCoefficient[Series[1728 *KleinInvariantJ[tau], {q, 0, n}], {q, 0, n}]]; Join[{1}, Table[(n + 1)*a[n], {n, 0, 50}]] (* G. C. Greubel, Feb 25 2017 *)
CROSSREFS
Sequence in context: A178449 A178451 A066395 * A294182 A091406 A066396
KEYWORD
nonn
STATUS
approved