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A161157
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a(n) = ((2^b-1)/phi(n))*Sum_{d|n} Moebius(n/d)*d^(b-1) for b = 15.
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1
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32767, 536821761, 78361756228, 4397643866112, 49998474112902, 1283800652283324, 3703889238001736, 36025498551189504, 124933950274693644, 819125001391673466, 1244326279702202508, 10516894943504990208, 10751334335850714158, 60680817386182440888
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OFFSET
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1,1
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LINKS
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FORMULA
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Sum_{k=1..n} a(k) ~ c * n^14, where c = (4681/2) * Product_{p prime} (1 + (p^13-1)/((p-1)*p^14)) = 4548.801953... .
Sum_{k>=1} 1/a(k) = (zeta(13)*zeta(14)/32767) * Product_{p prime} (1 - 2/p^14 + 1/p^27) = 3.05203853014...*10^(-5). (End)
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MATHEMATICA
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f[p_, e_] := p^(13*e - 13) * (p^14-1) / (p-1); a[1] = 32767; a[n_] := 32767 * Times @@ f @@@ FactorInteger[n]; Array[a, 20] (* Amiram Eldar, Nov 08 2022 *)
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PROG
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(PARI) a(n) = {my(f = factor(n)); 32767 * prod(i = 1, #f~, (f[i, 1]^14 - 1)*f[i, 1]^(13*f[i, 2] - 13)/(f[i, 1] - 1)); } \\ Amiram Eldar, Nov 08 2022
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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