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A161004
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a(n) = ((2^b-1)/phi(n))*Sum_{d|n} Moebius(n/d)*d^(b-1) for b = 12.
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2
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4095, 8382465, 362706435, 8583644160, 49987791945, 742460072445, 1349525501415, 8789651619840, 21417452280315, 102325010111415, 116835129114795, 760279114183680, 611574734464785, 2762478701396505, 4427568695944485, 9000603258716160, 8771463461234565
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OFFSET
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1,1
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LINKS
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FORMULA
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Sum_{k=1..n} a(k) ~ c * n^11, where c = (4095/11) * Product_{p prime} (1 + (p^10-1)/((p-1)*p^11)) = 723.3106628... .
Sum_{k>=1} 1/a(k) = (zeta(10)*zeta(11)/4095) * Product_{p prime} (1 - 2/p^11 + 1/p^21) = 0.0002443224366... . (End)
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MATHEMATICA
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f[p_, e_] := p^(10*e - 10) * (p^11-1) / (p-1); a[1] = 4095; a[n_] := 4095 * Times @@ f @@@ FactorInteger[n]; Array[a, 25] (* Amiram Eldar, Nov 08 2022 *)
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PROG
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(PARI) a(n) = {my(f = factor(n)); 4095 * prod(i = 1, #f~, (f[i, 1]^11 - 1)*f[i, 1]^(10*f[i, 2] - 10)/(f[i, 1] - 1)); } \\ Amiram Eldar, Nov 08 2022
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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