OFFSET
1,1
COMMENTS
The identity (256*n + 1)^2 - (256*n^2 + 2*n)*16^2 = 1 can be written as a(n)^2 - A158230(n)*16^2 = 1.
Also the identity (512*n + 1)^2 - (256*n^2 + n)*32^2 = 1 can be written as A076338(n)^2 - (n*a(n))*32^2 = 1. - Vincenzo Librandi, Feb 23 2012
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 1..10000
Vincenzo Librandi, X^2-AY^2=1
E. J. Barbeau, Polynomial Excursions, Chapter 10: Diophantine equations (2010), pages 84-85 (first identity in the comment section: row 15 in the initial table at p. 85, case d(t) = t*(16^2*t+2)).
Index entries for linear recurrences with constant coefficients, signature (2,-1).
FORMULA
a(n) = 2*a(n-1) - a(n-2); a(1)=257, a(2)=513. - Harvey P. Dale, Nov 21 2011
G.f.: x*(257-x)/(x-1)^2. - Harvey P. Dale, Nov 21 2011
MAPLE
MATHEMATICA
256Range[50]+1 (* or *) LinearRecurrence[{2, -1}, {257, 513}, 50] (* Harvey P. Dale, Nov 21 2011 *)
PROG
(Magma) I:=[257, 513]; [n le 2 select I[n] else 2*Self(n-1)-Self(n-2): n in [1..50]];
(PARI) a(n) = 256*n + 1.
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Vincenzo Librandi, Mar 14 2009
STATUS
approved